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全脑之王 汉字编码原创实用记忆学体系

>>>记忆法-记忆术-记忆道-记忆力-记忆学>>>

 
 
 

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《世界第一的记忆系统》  

2008-12-29 20:01:30|  分类: 记忆技术 |  标签: |举报 |字号 订阅

  下载LOFTER 我的照片书  |

[注]这套系统对于以英文为母语的人士而言,不失为一套有用的数字编码转换系统,但对于绝大多数中国人而言是不适用的。我们可以借鉴作者的设计原理,结合汉语言本身的个性和特点,来设计符合中国人的编码体系。

本文原发表于“中国记忆力训练网”。

 

中文版-BEN 记忆系统!

世界排名第一的记忆系统!

The 'Ben Pridmore System'

 

我的技巧并不是什么秘密,我十分高兴与各位分享,上年,我常在wwbc公开这方法,但因我们在这有了新的团体,那我会再公开它和会尽量简单易明.我并没给它“Ben system”这名字,但有很多人这样称它,而我也喜欢这名称.

这方法的基本原理与很多人使用的记法的相同的,把表象放在脑海内各地点(地点法),但我不是用“人物+动作+物品”这样记的,我只是将三样“东西”一起放在同一地点,这些“东西”有些是人物,有些是物品.我(想象)它们的排列是由左向右,或由上向下来分先后次序的,而它们之间会有相互作用自然发生.

每“一物”代表两张扑克牌,或3个十位数字(236457),或十个二进制数(0011000010).这一物的名称是由3个音节所组成的,子音+元音+子音=一物.

以下是扑克的音节代码:

第一个是子音,如下:

Club=草花,Diamond=方块,heart=红桃,spade=黑桃.

 

club/club - k

club/diamond - t

club/heart - n

club/spade – m

 

diamond/club - r

diamond/diamond - d

diamond/heart - l

diamond/spade - g/j

 

heart/club ?f/th

heart/diamond - b

heart/heart - h

heart/spade – p

 

spade/club - sk/sn/sm

spade/diamond - st/sp

spade/heart - sh/sl/sw

spade/spade ?s

 

接着是元音,如下:

A = `a' as in `cat'

2 = 'e' as in 'pet'

3 = 'i' as in 'kitten'

4 = 'o' as in 'tom'

5 = 'u' as in 'puss'

6 = `A' as in `hay'

7 = `E' as in `bee'

8 = `I' as in `high'

9 = `O' as in `low'

10 = `oo' as in `you'

J = `ow' as in `cow'

Q = `or' as in `door'

K = `ar' as in `car'

 

最后是子音,如下:

A = t

2 = n

3 = m

4 = r

5 = l

6 = g

7 = k

8 = f/th

9 = b

10 = s

J = j/sh/ch

Q = p

K = d

 

例如:红心A+梅花2=(红心+梅花=f)+ (a)A+ (n)2

=fan(风扇).又例如: (club+heart=n) + e (2) + t (Ace) = `net'(网).

 

这给了我2704个可同的物象.

 

数字上,我会使用相同的”物象”,但十位数字只需1000个代码,

而二进制就需要1024个代码.看下表:

 

第一个子音(第一个数字)

0 = s

1 = t

2 = n

3 = m

4 = r

5 = l

6 = gj

7 = k

8 = f/th

9 = b

 

元音(第二个数字)

 

0 = `oo'

1 = `a'

2 = 'e'

3 = 'i'

4 = 'o'

5 = 'u'

6 = `A'

7 = `E'

8 = `I'

9 = `O'

子音(第三个数字)

0 = s

1 = t

2 = n

3 = m

4 = r

5 = l

6 = g

7 = k

8 = f/th

9 = b

 

而二进制数字是这样,如下:

 

首子音(首4个数字)

 

0000 = s

0001 = t

0010 = n

0011 = m

0100 = r

0101 = l

0110 = g/j

0111 = k

1000 = f

1001 = b

1010 = p

1100 = h

1101 = sk/sn/sm

1110 = st/sp

1111 = sh/sl/sw

 

元音(接着的三个数字)

 

000 = `oo'

001 = `a'

010 = 'e'

011 = 'i'

100 = 'o'

101 = 'u'

110 = `A'

111 = `E'

 

子音(最后三个数字)

 

000 = s

001 = t

010 = n

011 = m

100 = r

101 = l

110 = g

111 = k

 

我希望这足够明白易懂.我非常欢迎回答来问!

我现在是否很久没练扑克和二进制数?在上年,我没有认真练习过,我在前三个月只集中精神记圆周率,但我肯定我仍熟记以上的代码,所以如果我再开始训练,我应该能够很快可以运用以上的技巧,希望如此. 

BEN

原文如下:

The 'Ben Pridmore System'

 

My techniques aren't a secret, I'm quite happy to share them with anyone who's interested. I normally point people towards the wwbc posts last year where I explained it, but since we've got a brand new group here, I've rewritten it and made it hopefully a bit easier to understand. I don't actually call it the 'Ben system', but that's what some people have been calling it, and I do quite like the name.

It's really just an extension of the basic Major system.

 

The basic principle is the same as everyone else uses, visualising images at points along a mental route or journey. I don't use the person-action-object ideas of some people, I just have three `objects' at each point on my route. Some of these objects are people, some are things. I `see' them arranged from left to right,or top to bottom, and interacting in various ways according to rules I made up as I went along, depending on which objects come together in what order.

 

Each object is made from a combination of two playing cards, or three decimal digits, or ten binary digits. The name of the object starts with a one-syllable sound made up of a consonant, a vowel and another consonant. For playing cards, these sounds are made as follows. 

The first consonant is given by the combination of suits, like this:

 

club/club - k

club/diamond - t

club/heart - n

club/spade - m

diamond/club - r

diamond/diamond - d

diamond/heart - l

diamond/spade - g/j

heart/club ?f/th

heart/diamond - b

heart/heart - h

heart/spade - p

spade/club - sk/sn/sm

spade/diamond - st/sp

spade/heart - sh/sl/sw

spade/spade ?s

 

The vowel comes from the number/rank of the first card, like this:

 

A = `a' as in `cat'

2 = 'e' as in 'pet'

3 = 'i' as in 'kitten'

4 = 'o' as in 'tom'

5 = 'u' as in 'puss'

6 = `A' as in `hay'

7 = `E' as in `bee'

8 = `I' as in `high'

9 = `O' as in `low'

10 = `oo' as in `you'

J = `ow' as in `cow'

Q = `or' as in `door'

K = `ar' as in `car'

 

And the final consonant comes from the number of the second card,

like this:

 

A = t

2 = n

3 = m

4 = r

5 = l

6 = g

7 = k

8 = f/th

9 = b

10 = s

J = j/sh/ch

Q = p

K = d

 

So, for example, Ace of hearts + 2 of clubs gives f (heart/club) + a(Ace) + n (2) = `fan'. If the 2 of clubs came first it would be n(club/heart) + e (2) + t (Ace) = `net'.

 

That gives me 2704 different images. For numbers, I use the same list of images, but only use 1000 of them for decimal and 1024 for binary. It works like this:

 

First consonant (first digit)

 

0 = s

1 = t

2 = n

3 = m

4 = r

5 = l

6 = gj

7 = k

8 = f/th

9 = b

 

Vowel (second digit)

 

0 = `oo'

1 = `a'

2 = 'e'

3 = 'i'

4 = 'o'

5 = 'u'

6 = `A'

7 = `E'

8 = `I'

9 = `O'

 

Second consonant (third digit)

 

0 = s

1 = t

2 = n

3 = m

4 = r

5 = l

6 = g

7 = k

8 = f/th

9 = b

 

And for binary, it's: 

First consonant (first four digits)

 

0000 = s

0001 = t

0010 = n

0011 = m

0100 = r

0101 = l

0110 = g/j

0111 = k

1000 = f

1001 = b

1010 = p

1100 = h

1101 = sk/sn/sm

1110 = st/sp

1111 = sh/sl/sw

 

Vowel (next three digits)

 

000 = `oo'

001 = `a'

010 = 'e'

011 = 'i'

100 = 'o'

101 = 'u'

110 = `A'

111 = `E'

 

Second consonant (final three digits)

 

000 = s

001 = t

010 = n

011 = m

100 = r

101 = l

110 = g

111 = k

 

I hope that's clear. I'm always happy to answer questions! 

I'm very out of practice with the cards and binary now ?I haven't really done any training since last year, and I've been concentrating on memorising pi for the last three months. I'm pretty sure I can still remember the list of images, so I should be able to just click back into the swing of it if I start training again, I hope. 

Ben

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